3AS U03 - E5 - Exercice 009

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    3AS U03 - Exercice 001

    :) 2011- ((**)

    C E = 6V. C R = 4 k.

    1-

    .2- uC(t) . -

    t = 0 ms

    :t (ms) 0 10 20 30 40 60 80 100 120

    uC(V) 6.00 4.91 4.02 3.21 2.69 1.81 1.21 0.81 0.54

    - uC= f(t) .

    -

    .

    -

    C.3--

    uC(t).

    -

    uC(t) = A e

    -t

    A

    .

    : .

    :01/09/2014

    : .

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    Sujet : 2AS 02 - 01

    1-

    :

    2--

    .

    -

    )t(f=Cu:

    -

    :t = uC= 0.37 E = 0.37 . 6 = 2.22 V := 50 ms.

    :-

    F12.5=F10.1.25=10.4

    10.50=

    R

    =CRC= 5-3

    3-

    3--

    Cu:

    :

    0 = uR+ uCR i + uC= 0

    V

    0

    1

    2

    3

    4

    5

    6

    7

    0 50 100 150

    t (ms)

    U C(V) )V(UC

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    : :

    0=u+dt

    duCR C

    C

    0=uRC

    1+

    dt

    duC

    C

    -A

    : eA=u t-C

    eA-=dt

    du t-C

    :

    0=eRC

    A+eA- t-t-

    :

    RC

    1=

    RC

    A=A

    :t = 0 uC= 6 = E

    eA=u t-C :

    E = A e-(0)

    A = E