Report - CALCUL INTÉGRAL...∫x sin x dx =-x2 cosx +2xsin x +2cosx +C 5. Soit u =ln x et dv =x dx. Alors , 2 1 2 et x dx v x du = = de sorte que dx x x x x x x dx 1 2 ln 2 ln 2 ∫ = −∫

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