Math In FM

download Math In FM

of 59

Transcript of Math In FM

  • 7/29/2019 Math In FM

    1/59

    Chapter 5Mathematics of Finance

    Section 5.1 Simple Interest

    Section 5.2 Compound Interest

    Section 5.3 Annuities and Sinking Funds

    Section 5.4 Present Value of an Annuity and

    Amortization

  • 7/29/2019 Math In FM

    2/59

    Simple Interest

    Simple interest is most often used for loans of shorter

    duration.

    The money borrowed in a loan is called theprincipal.

    The number of dollars received by the borrower is the

    present value.

    In a simple interest loan, the principal and present value

    are the same. The interest rate is the fee for a simple interest loan and

    usually is expressed as a percent of the principal.

    Simple interest is paid on the principal borrowed and

    not paid on interest already earned.

    Section 5.1

  • 7/29/2019 Math In FM

    3/59

    Simple Interest

    I=Prtwhere P= principal (amount borrowed)

    r= interest rate per year (in decimal form)

    t= time in years.

    The simple interest of a loan can be calculated using the

    following formula.

  • 7/29/2019 Math In FM

    4/59

    Example

    An individual borrows $300 for 6 months at 1% simple

    interest per month. How much interest is paid?

    SOLUTIONRemember to check that rand tare consistent in time

    units. Here, it will be months.

    I=Prt= 300 0.01 6 = $18

  • 7/29/2019 Math In FM

    5/59

    Another Example

    Jane borrowed $950 for 15 months. The interest was

    $83.13. Find the interest rate.

    SOLUTION

    First, determine the information we have been given.

    P= 950

    t= 15/12 = 1.25 years

    I= 83.13

    UsingI=Prt, we need to find r

    83.13 950 (1.25)1187.5

    83.130.07

    1187.5

    r

    r

    r

    The interest rate was 7%.

  • 7/29/2019 Math In FM

    6/59

    Future Value

    A loan made at simple interest requires that the borrower pay

    back the sum borrowed (principal) plus the interest. This total

    is called thefuture value, oramountand is equal toP+I.

    A =P+I

    = P + Prt

    = P(1 + rt)

    where P= principal or present value

    r= annual interest rate (in decimal form)

    t= time in years

    A = amount or future value

  • 7/29/2019 Math In FM

    7/59

    Total Number of Compounding Periods

    Annual Interest rate expressed as a percent

    Present Value: What it is worth to you right now

    Amount of the payment being made if any.

    Future Value: What it will be worth to you

    in the future

    The number of payments per year

    The number of compounds per year.

    Is Interest/Payment due at the beginning or

    end of the compound period?

  • 7/29/2019 Math In FM

    8/59

  • 7/29/2019 Math In FM

    9/59

    Example

    Find the amount (future value) of a $2400 loan for 9 months

    at 11% interest.

    SOLUTIONWe need to findA which equalsP+I=P+Prt.

    Now, determine the information we have been given.9

    122400, 0.11, and 0.75 yearsP r t

    FindI: I= 2400(0.11)(0.75) = 198Now, findA: A = 2400 + 198 = 2598

    A could have also been found

    using the formulaA =P(1 + rt)

    2400(1 0.11(0.75))2400(1 0.0825)2400(1.0825)2598

    A

  • 7/29/2019 Math In FM

    10/59

    Simple Discount

    The simple discount loan differs from the simple interest

    loan in that the interest is deducted from the principal and

    the borrower receives less than the principal.

    This type of loan is referred to as asimple discount note.

    The interest deducted is the discount.

    The amount received by the borrower is theproceeds.

    The discount rate is the percentage used.

    The amount repaid is the maturity value.

  • 7/29/2019 Math In FM

    11/59

    Simple Discount Note

    D =Mdt

    PR = MD

    = M

    Mdt= M(1dt)

    where M= maturity value (principal)

    d= annual discount rate (in decimal form)t= time in years

    D = discount

    PR = proceeds or amount the borrower receives

  • 7/29/2019 Math In FM

    12/59

    Example

    Find the discount and the amount a borrower receives (proceeds)

    on a $1500 simple discount loan at 8% discount rate for 1.5

    years.

  • 7/29/2019 Math In FM

    13/59

    Example

    A bank paid $987,410 for a 90-day $1 million treasury

    bill. What was the simple discount rate?

  • 7/29/2019 Math In FM

    14/59

    Example

    A bank wants to earn 7.5% simple discount interest on a

    90-day $1 million treasury bill. How much should it bid?

    SOLUTIONFirst, determine what information is given.

    90

    3601,000,000, 0.075, and 0.75 yearsM d t

    We need to find the proceeds which equalsPR.

    90360

    1,000,000 1 (0.075)

    1,000,000 1 0.01875

    1,000,000 0.98125

    981,250

    PR

    The bank should bid $981,250.

  • 7/29/2019 Math In FM

    15/59

    Example

    How much should a bank bid on a 30-day $2 million

    treasury bill if the bank wants to earn 5.125% on its money.

  • 7/29/2019 Math In FM

    16/59

    HW 5.1

    Pg 348-350 1-32, 34-64 even

  • 7/29/2019 Math In FM

    17/59

    Compound Interest

    Section 5.2

    Suppose you deposit money into a savings account, the bank

    will typically pay you interest for the use of your money at a

    specific period of time, say every three months. The interest

    is usually credited to your savings account at each timeperiod. At the next time period, the bank will pay interest on

    the new total, this is called compound interest.

    Amount of Annual Compound Interest

    WhenPdollars are invested at an annual interest rate randthe interest is compounded annually, the amountA at the end

    oftyears is

    A =P(1 + r)t

  • 7/29/2019 Math In FM

    18/59

    Example

    Suppose $800 is invested at 6%, and it is compounded

    annually. What is the amount in the account at the end

    of 4 years?

    SOLUTION `

    First, determine the information that is given.

    P= 800, r= 0.06, and t= 4

    4800(1.06) 800(1.26248) 1009.98A

    There will be $1009.98 in the account after 4 years.

  • 7/29/2019 Math In FM

    19/59

    Amount (Future Value)

    The general formula for finding the amount after a specified number

    of compound periods is

    A =P(1 + i)n

    where r= annual interest rate

    m = number of times compounded per year

    i = r/m = interest rate per periodn = mt, the number of periods, where tis the number of years

    A = amount (future value) at the end ofn compound periods

    P= principal (present value)

  • 7/29/2019 Math In FM

    20/59

  • 7/29/2019 Math In FM

    21/59

    Example

    Suppose $800 is invested at 12% for 2 years. Find the amount

    at the end of 2 years if the interest is compounded (a)

    annually, (b) semiannually, and (c) quarterly.

    SOLUTION

    First, determine what information is given then useA =P(1 + i)n.

    P= 800, r= 0.12, and t= 2 years.

    2 2800(1 0.12)

    a) 1, so

    8

    0.12/1 0.

    00(1.12) 800(1.2544) 1003.5

    12, 2;

    2A

    m i n

    4 4800(1 0.06) 800(1.06) 800(1.26248)b) 2, so 0.12/ 2 0.06, 4;

    1009.98m

    A

    i n

    8 8800(1 0.03) 800(1.03) 800(1.26677)

    c) 4, so 0.12/4 0.03, 8;

    1013.42

    m

    A

    i n

  • 7/29/2019 Math In FM

    22/59

    Total Number of Compounding Periods

    Annual Interest rate expressed as a percent

    Present Value: What it is worth to you right now

    Amount of the payment being made if any.

    Future Value: What it will be worth to you

    in the future

    The number of payments per year

    The number of compounds per year.

    Is Interest/Payment due at the beginning or

    end of the compound period?

  • 7/29/2019 Math In FM

    23/59

    (compounds per year)(# of years)

    Annual Interest rate expressed as a percent

    Present Value: What it is worth to you right now

    0

    Future Value: What it will be worth

    Compounds per year

    Always on End

  • 7/29/2019 Math In FM

    24/59

    Example

    Suppose $800 is invested at 12% for 2 years. Find the amount at

    the end of 2 years if the interest is compounded (a) annually

    1(2) 1 compound every year for two years

    12 Yearly interest rate

    -800 The amount being invested todayPresent Value

    0 No regular payments are being made

    What we want to solve forAlpha Enter

    1There is 1 compound per year

    1

    1003.52

  • 7/29/2019 Math In FM

    25/59

    Example

    Suppose $800 is invested at 12% for 2 years. Find the amount at

    the end of 2 years if the interest is compounded (b) semiannually

    2(2) 2 compound every year for two years

    12 Yearly interest rate

    -800 The amount being invested todayPresent Value

    0 No regular payments are being made

    What we want to solve forAlpha Enter

    2There are 2 compound per year

    2

    1009.98

  • 7/29/2019 Math In FM

    26/59

    Example

    Suppose $800 is invested at 12% for 2 years. Find the amount at

    the end of 2 years if the interest is compounded (c) quarterly.

    4(2) 4 compound every year for two years

    12 Yearly interest rate

    -800 The amount being invested todayPresent Value

    0 No regular payments are being made

    What we want to solve forAlpha Enter

    4There is 4 compound per year

    4

    1013.42

  • 7/29/2019 Math In FM

    27/59

  • 7/29/2019 Math In FM

    28/59

    1(5) 1 compound every year for five years

    What we want to solve forAlpha Enter

    -100 We do not know the present value so use $100

    0 No regular payments are being made

    If we started with $100 and we want to double it?

    1There is 1 compound per year

    1

    14.8698355

    200

  • 7/29/2019 Math In FM

    29/59

  • 7/29/2019 Math In FM

    30/59

    Vocabulary

    Nominal Rate

    Compound rate thatreturns the same total

    value as a simpleinterest investment.

    Effective Rate

    simple interest rate

    that produces thesame total value ofinvestment per yearas the compoundinterest.

  • 7/29/2019 Math In FM

    31/59

    Effective Rate

    The effective rate of an annual interest rate rcompounded m

    times per year is the simple interest rate that produces the same

    total value of investment per year as the compound interest.

    If money is invested at an annual rate rand compounded m

    times per year, the effective rate,x, in decimal form is

    x = (1 + i)m1 where i = r/m

  • 7/29/2019 Math In FM

    32/59

    Example

    The Mattson Brothers Investment Firm advertises Certificates of

    Deposit paying a 7.2% effective rate. Find the annual interest

    rate, compounded quarterly, that gives the effective rate.

    SOLUTIONIf we let i = quarterly rate, then

    4

    4

    4

    0.072 (1 ) 11.072 (1 )

    1.072 11.017533 10.017533

    i

    i

    ii

    i

    The annual rate = 4(0.017533) = 0.070133 = 7.013% (rounded).

    The annual rate just found is also called the nominal rate.

  • 7/29/2019 Math In FM

    33/59

    HW 5.2

    Pg 359-360 1-17 odd, 18-63 every 3rd

    Section 5 3

  • 7/29/2019 Math In FM

    34/59

    Ordinary Annuity

    An annuity refers to equal payments paid at equal time

    intervals.

    The time between successive payments is called the

    payment period.

    The amount of each payment is theperiodic payment.

    The interest on an annuity is compound interest.

    An ordinary annuity is an annuity with periodic payments

    made at the end of each payment period.

    Section 5.3

  • 7/29/2019 Math In FM

    35/59

    Future Value (Amount)

    Payments are made at the end of each period.

    where i = interest rate per period

    n = number of periods

    R = amount of each periodic paymentA = future value of amount

    (1 ) 1n

    iA R

    i

  • 7/29/2019 Math In FM

    36/59

    Example

    How much money will you have when you retire if you save $20

    each month from graduation until retirement? Lets assume you

    start saving at age 22 until age 65, 43 years, and the interest rate

    averages 6.6% annual rate compounded monthly.SOLUTION

    The periodic rate = 0.066/12 = 0.0055 since payments are

    made monthly. The number of periods is n = 12(43) = 516.

    The periodic payments areR = 20. Substitute these valuesinto the formula for future value.516(1 ) 1 (1.0055) 1

    20 57,997.300.0055

    ni

    A Ri

    You will accumulate $57,997.30 in 43 years.

    How much money will you have when you retire if you save $20 each

  • 7/29/2019 Math In FM

    37/59

    How much money will you have when you retire if you save $20 each

    month from graduation until retirement? Lets assume you start saving at

    age 22 until age 65, 43 years, and the interest rate averages 6.6% annual

    rate compounded monthly.

    12(43) 12 compounds every year for 43 years

    6.6 Yearly interest rate

    0 The amount being invested todayPresent Value-20 You are putting 20 per month in the account

    What we want to solve forAlpha Enter

    12

    There is 12 compound per year12

    57997.30

  • 7/29/2019 Math In FM

    38/59

    1(20) 1 compounds every year for 20 years

    8.5 Yearly interest rate

    0 The amount being invested todayPresent Value-2000 You are putting 2000 per year in the account

    What we want to solve forAlpha Enter

    1

    There is 1 compound per year1

    96754.03

  • 7/29/2019 Math In FM

    39/59

  • 7/29/2019 Math In FM

    40/59

  • 7/29/2019 Math In FM

    41/59

  • 7/29/2019 Math In FM

    42/59

  • 7/29/2019 Math In FM

    43/59

    Sinking Funds

    A sinking fund refers to a fund that is created when an amount of

    money will be needed at some future date. For example, a family

    may need a new car in 3 years, or a company may expect to

    replace a piece of equipment in the future.

    Formula for Periodic Payments of a Sinking Fund

    where A = value of the annuity after n payments

    n = number of payments

    i = periodic interest rate

    R = amount of each periodic payment

    (1 ) 1

    n

    AiR

    i

  • 7/29/2019 Math In FM

    44/59

    ExampleDarden Publishing Company plans to replace a piece of

    equipment at an expected cost of $65,000 in 10 years. The

    company establishes a sinking fund with annual payments.

    The fund draws 7% interest, compounded annually.

    What are the periodic payments?

    SOLUTION

    First, determine the information that is given.

    10

    65,000, 0.07, and 10

    65000(0.07) 45504704.54

    (1.07) 1 0.9671513

    A i n

    R

    The annual payments are $4704.54.

  • 7/29/2019 Math In FM

    45/59

  • 7/29/2019 Math In FM

    46/59

  • 7/29/2019 Math In FM

    47/59

  • 7/29/2019 Math In FM

    48/59

  • 7/29/2019 Math In FM

    49/59

  • 7/29/2019 Math In FM

    50/59

    HW 5.3

    Pg 372-374 1-47 odd

    Section 5.4

  • 7/29/2019 Math In FM

    51/59

    Present Value

    Section 5.4

    The present value of an annuity is the lump sum payment

    that yields the same total amount as that obtained through

    equal periodic payments made over the same period of time.

    The present value of an annuity is

    where i = periodic rate

    n = number of periods

    R = periodic payments

    P= present value of the annuity

    (1 ) 1 1 (1 )

    (1 )

    n n

    n

    i iP R R

    i i i

  • 7/29/2019 Math In FM

    52/59

    Example

    Find the present value of an annuity with periodic payments

    of $2000, semiannually, for a period of 10 years at an interest

    rate of 6% compounded semiannually.

    SOLUTIONUse the values given,R = 2000, i = 0.06/2 = 0.03 and n = 20

    in the formula for present value.20 20

    20

    (1 ) 1 (1.03) 1 1 (1 0.03)2000 2000

    (1 ) 0.03(1.03) 0.03

    2000(14.8774749) 29754.95

    n

    n

    iP R

    i i

    The present value of the annuity is $29,754.95. This lump sum

    will accumulate the same amount in 10 years as investing $2000

    semiannually for 10 years.

  • 7/29/2019 Math In FM

    53/59

    Equal Periodic Payments

    The amount needed to provide equal periodic

    payments can be found using the formula

    or equivalently,

    where P= amount needed in the fund

    R = amount of periodic payments

    i = periodic interest rate

    n = number of payments

    (1 ) 1

    (1 )

    n

    n

    iP R

    i i

    1 (1 ) niP R

    i

  • 7/29/2019 Math In FM

    54/59

    Example

    Find the present value of an annuity (lump sum investment)

    that will pay $1000 per quarter for 4 years. The annual

    interest rate is 10%, compounded quarterly.

    SOLUTION

    16

    0.01Given 1000, 0.025, and 16 quarters,

    4

    1 (1.025)

    1000 0.025

    1000(13.0550027) 13,055

    R i n

    P

    A lump sum investment of $13,055 will provide $1000 per

    quarter for 4 years.

  • 7/29/2019 Math In FM

    55/59

    Amortization

    The amortization of a debt (repayment of a debt) requires no

    new formula because the amount borrowed is just the

    present value of an annuity.

    Amortization of a Loan (Debt Payments)The amount borrowed,P, is related to the periodic payments,R,

    by the formula

    where i = periodic interest rate

    n = number of payments

    Note: This is the present value formula for an ordinary annuity.

    (1 ) 1 1 (1 )

    (1 )

    n n

    n

    i iP R R

    i i i

  • 7/29/2019 Math In FM

    56/59

    Example

    A student obtained a 24-month loan on a car. The monthly

    payments are $395.42 and are based on a 12% interest rate.

    What was the amount borrowed?

    SOLUTION

    Since the amount borrowed is the present value of the

    annuity, we have

    395.420.12

    0.0112

    24

    R

    i

    n

    (Monthly rate)

    (Number of months)

    241 (1.01)

    395.42

    0.01

    395.42(21.2433873)

    8400.06

    P

    The amount borrowed was $8400.

  • 7/29/2019 Math In FM

    57/59

    Balance of an Amortization

    The balance aftern periods is the amount of compound

    interest minus the amount of an annuity. Mathematically we

    can find the balance using the formula

    (1 ) 1Balance (1 )

    nn i

    P i Ri

    where P= the amount borrowed

    i = periodic interest raten = number of time periods elapsed

    R = monthly payments

  • 7/29/2019 Math In FM

    58/59

    ExampleA family borrowed $60,000 to buy a house. The loan was for

    30 years at 12% interest rate. The monthly payments were

    $617.17. What is the balance of their loan after 2 years?

    SOLUTION 1212

    60,000, 1% per month, 617.17, 24 monthsP i R n 24

    24 (1.01) 1Balance 60,000(1.01) 617.17

    0.01

    60,000(1.26973) 617.17(26.9734649)76,184.08 16,647.21

    59,536.87

    The part of the loan repaid is the equity which after

    2 years is is 60,00059,536.87 = $463.13.

    This is the balance of the

    loan after two years.

  • 7/29/2019 Math In FM

    59/59

    HW 5.4

    Pg 389-391 1-47 Odd