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    Engine geometry

    AndOperating Characteristics

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    engine is really

    indicated inside the

    work, power, mep etc.

    engine is actually

    work, power, mep

    shaft.

    ii- indicated ; is what the

    producing, that is

    cylinder in terms of

    iii- brake ;is what the

    delivering, similarly the

    measured at the output

    power

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    inefficiency

    iv- the values of the two

    parameters is always

    given as )indicated l under square )large engines(

    d < l over square

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    5. Compression ratio r

    r =VBDC /VTDC

    =) Vd +Vc)/Vc

    8 SI 11

    12 CI 24

    3. Average piston speed

    5 Up 15m/s

    Up 15 m/s engine high performance automobile

    5 Up m/s large diesel engine

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    4. Engine speed

    200-40012000- higher Up accelerates &decelerates twice in each crankrpm

    So N- and t- for each rpmhence, Up- as N -

    .Alimit must be set to avoid material strengthfailure in components like piston and con rod.

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    .1Clearance volume (Vc)

    this is the minimum volume

    in the combustion

    chamber with the pistonat the TDC

    .2 Displacementvolume(Vst)

    volume swept by the pistonas it travels through one

    stroke

    .3Total volume (Vt(

    Is the sum of Vc &Vst

    Vt =Vc +Vd

    .4TDC &BDC

    Vc =VTDC

    Vt =VBDC

    Related volumes

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    From which)Vc) can be expressed as:

    Compression ratio )Cr(

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    P = F/A

    P = pressure acting onforce is exerted.

    combustion

    Pg =gas pressure inside

    Work )W) is always the

    force )F) exerted over a

    distance (x (. When there is no movementof an

    object, there will be no work

    done,regardless of how much

    W =F .X

    W =work (kJ/kg(

    F =force

    x =distance piston moves

    But since

    F =P .A

    A =piston face area

    piston face due to

    P =Pg Pc

    the cylinder due to

    combustion process

    Pc =pressure in crank case

    work

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    mass, the expression

    Specific work; is the

    of AF mixture:

    And specific volume is

    work )w) is

    Sub and rearrangeW =P .A .X For small displacement(dx(

    dW =P .A .dx

    Where )A. dx =dV) incrementalswept volume

    So, dW =P. dV

    Therefore;

    W =P.dV

    Where )P.dV ) is thearea under the PVdiagram

    When considering unit

    specific is used, i.e

    work done per unit mass

    w =W/m

    v =V/m

    Therefore the specific

    w =P. dv

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    +)ve) whenthegas

    expansionstroke(

    compressedandthe

    **The specificwork is

    producingthepressureis

    expanding )poweror

    **The specificwork is

    )- ve) whenthegasis

    workisdoneonthegasbytheoutsidesource.

    In this equation if )P) is the

    pressure inside the cylinder,

    then thework is the indicatedwork )w)i.

    however, the actual work

    delivered by the crank shaft is

    the brakework )w)b ,and

    )w)i - )w)b ) =w)l

    Where )w)l is the specific work

    lost

    )w)l =] friction +parasitic[

    specific workThe units representing work is

    )kJ/kg(

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    W =mep .Vd

    mep =w/Vd =w/ v

    TDCBDC

    Since )mep) is related to

    (w (,

    the equation determines the

    Due to piston motion andstroke, the pressureinside the cylinder iscontinuously changing

    during the cycle, and therefore we can

    define )mep) as

    the everage pressure

    acting on the pistonthrough the power

    stroke

    So, the work done bymep is:

    W =P.dV

    Then

    v = v -v

    then the type of )w) used in

    type of (mep.(

    Mean effective pressure (mep(

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    For SI engines

    (w)b bmep(w)i imep(w)pump pmep

    (w)frictionfmep if gmep is gross mep and nmep is net mep

    nmep =gmep +pmep

    bmep =nmep fmepbmep =imep fmep

    bmep =m .imep

    For typical engines

    850kPa bmep 1050kPa

    forCI engines

    kPa700 bmep 900kPa

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    Calculation of engine

    power output can be

    done in several

    methods, since thedefinition of power is

    the rate at which

    engine is doing work,then power is related

    to work and speed.

    Power ((

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    1. Related to work

    = W . (N/n)W : work (kJ/kg)

    N : engine speed (rpm x 1/60) rps

    n = 2 for 4 stroke engine

    = 1 for 2 stroke engine

    = power output (kW)

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    The conversion factor )C (

    C =4500 for )metrichp(

    C =6120 for (kW(

    2c. Related to (mep(

    =k[PLAN/n] /CWhere:

    C =conversion factork =number of cylinders

    =power output )kW, metric hp(P =mep )kgf/cm (

    L =piston stroke )m)A =piston cross section area (cm (N =engine speed (rpm(

    n =rev/cycle

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    get

    3. Related to mean Up

    = [PLAN/n] / CSince

    L= stroke (S)N= engine speed

    And

    Up = 2LN = 2SN

    ThenUp/2 = LN

    Sub in equation to

    =] P. A.Up] /n C

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    swept volume (m (

    )N/60n) :rev/s

    a =is the air mass rate

    a =v .Vd .a .) N/60n(

    a : air mass rate kg/s

    v : volumetric efficiency

    Vd =/ 4d l

    a =Pin/(Rg.Tin)

    inlet air density

    Pin (kPa (

    Rg =0.287 kJ/kg.k

    Tin )deg. K(

    4. Related to combustion

    =f .CV .th.i

    Also since

    FA =f/a

    or AF =a /f

    then f =FA. a

    )=FA.a) CV .th.i

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    From above equation, we can notice the followings:

    If either )mf) or )AF) is given then, the power can be evaluated

    engine geometry is known.

    Considering the term )CV .th.i(

    if

    CV - is the fuel calorific value which is the fuel heating

    value (Q).

    - is the thermal efficiency of the engine cycle, which

    means the fraction of heat liberated from fuel(CV . th.i ) that could be converted to mechanical

    energy.

    th.i

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    In general power output =heat energy in fuel x abilityof conversion

    What is the engine ability of conversion

    In this respect, ability of conversion is best looked at through terms of efficiencies:

    c -combustionefficiency, which is the ability of how much of the fuel that can really

    be burned.

    f - fuel conversion efficiency, which is the ability of how much heat energy canreally be converted to power.

    So [f . CV] determines the total heat that can possibly be produced by combustionprocess.

    Using the above efficiencies :Heat input to the engine

    Qin= f . CV . c

    Poweroutput from engine

    =f .CV. f

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    th = f .CV. f /f. CV . c

    Heat input to the engine

    Qin =f .CV . c Power output from

    engine

    =f .CV. f

    th. -is the thermalefficiency

    th = /Qin

    th =f / c

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    From all of the previous equations, power

    correlation can be summarized as follows:

    1. =W .) N/n(

    2. =] PLAN/n] /C

    3. =] P. A.Up] /n C

    4. =f

    .CV .th.

    5. =2 N

    summary

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    2 =W/nAnd

    obtain torque-powercorrelation

    Torque is a force acting ata distance, measured in(N.m.(

    Or more specifically

    torque is a force that ,when applied, results in

    twisting an object rather

    than its physical

    movement .Analytically, torque is

    2 = W/n =bmep.Vd/n =bmep.Vd/ 2 n

    Since =W ) .N/n(

    Using the common factor )W)to

    =2 N

    Engine Torque

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    correlation depends on the power used

    i.e

    units(gm/kW.hr(

    sfc =fuel mass rate /engine power

    sfc =f/The indicated or brake (sfc) in this

    isfc =f / i

    bsfc =f

    /bThe )sfc) is usually measured in the

    Specific fuel consumption

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    are more commonly used, i.e

    AF =a /f )mass rates kg/s(

    Fuel/air ratio =fuel/air =FA

    FA =mf /ma )mass kg()combustion) safe and

    rates are set in such a values

    Oxygen, from ambient air, isneeded in the engine cylinder

    to chemically react with fuel

    HC constituents.

    In order to control suchchemical reaction

    )combustion), there must be a

    limit set upon both reactants

    to keep the reaction

    economical.

    Therefore air and fuel mass

    that satisfy such requirements

    The ratios of both mass rates

    Air/fuel ratio =air/fuel =AF

    AF =ma /mf )mass kg(

    FA =f /a )mass rates kg/s(

    It is useful to acknowledge that

    AF =1/ FAand

    FA =1/ AF

    Air /fuel mixture

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    process (AF)a differ from

    (to be discussed later).the engine to completely react

    appears called the

    stoichiometric)AF)stor )FA)st .

    ) =FA)a /) FA)st

    In actual combustion

    )AF)st due to many causes

    So new expressionequivalence ratio

    ) =AF)st ) /AF)a

    =1 stoichiometric >1 lean )O2 in exh(.