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    Sums of Independent Random

    Variables

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    4. Approximations

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    Theorem 4.1 (Chebyshev

    Inequality)

    LetXbe random variable with mean and variance 2.

    Then for any and let > 0

    2

    2.P X

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    Proof

    2

    2

    2

    2

    x

    x e

    V X x f x dx

    x f x dx

    f x dx

    P X

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    Theorem 4.2 (Law of Large

    Numbers)

    LetX1,X2, ... ,Xnbe an independent and identically

    distributed random variables with mean and variance

    2. Let Sn=X1+X2++Xn. Then for any real number

    > 0 we have

    lim 0 .n

    n

    SP

    n

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    Proof

    12

    2

    2 21

    2

    2 0

    Note that

    1 1

    1 1 .

    By Chebyshev inequality

    lim 0 .

    nn

    n

    in

    nn

    i

    n n

    x

    SE E S

    n n n

    SVar Var S

    n n n n

    S SnP P

    n n

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    Example 4.1

    Let Ebe an event and define independent randomvariablesXisuch thatXiis 1 if the event Eoccurs

    andXiis 0 otherwise. Letp= P(E).

    Then E(Xi) =pand

    This gives a mathematical justification to the

    relative frequency interpretation of probability.

    lim 0.nn

    SP p

    n

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    Convergence in Distribution

    LetX1,X2, ... be a sequence of random variablesand let Fibe the distribution ofXifor each i. LetX

    be a random variable with distribution F. We say

    thatXnconverges in distribution toXif

    lim for all .nn

    F x F x x

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    Theorem 4.3

    LetX1,X2, ... be a sequence of random variablesand let ibe the mgf ofXi for each i. LetXbe a

    random variable with mgf . ThenXnconverges in

    distribution toXif

    for all tin some neighborhood of 0.

    lim nn

    t t

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    Poisson Approximation to the

    Binomial

    LetX1,X2, ... be independent Binomial randomvariables with parameters nandp. Suppose that

    limnnp= . ThenXnconverges in distribution to a

    Poisson random variable with mean .

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    1

    1

    11

    1Now, lim 1 and lim .

    Hence,

    lim .

    t

    t

    nt

    nt

    n

    nte

    n n

    e

    nn

    np et pe q

    n

    ee np

    n

    t e

    Proof

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    Example 4.2

    An airline finds that 4 percent of the passengersthat make reservations on a particular flight will not

    show up. Consequently, their policy is to sell 100

    reserved seats on a plane that has only 98 seats.

    Find the probability that every person who showsup for the flight will find a seat available.

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    Solution

    LetXbe the number of passengers who do notshow up. ThenXis binomial with parameters n=

    100 andp= .04 . We want P(X 2). Using Poisson

    approximation

    4 42 1 4 .908.P X e e

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    Theorem 4.4

    LetX1,X2, ... ,Xnbe independent and identicallydistributed Normal random variables with mean

    and variance 2. Define

    Then has a standard Normal

    distribution.

    1 2

    .

    n

    n

    X X X

    X n

    n nZ n X

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    Proof

    2

    1

    2

    1 1

    Let . We have shown previously that

    has a standard normal distribution.

    1 .

    n i

    i i

    i

    nn

    n i

    i

    n nt n

    Z Y

    i i

    Y X

    Y

    XZ n Yn

    tt e

    n

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    Theorem 6.5 (Central Limit Theorem)

    LetX1,X2, ... ,Xnbe independent and identicallydistributed random variables with mean and

    variance 2. Define

    Then converges in distribution to

    a standard Normal distribution.

    1 2 .nnX X XX

    n

    n nZ n X

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    Proof

    2

    2

    Let . Then

    1 0 0 0

    2with lim 0.

    But 0 1, 0 0 and 0 1. Hence

    1 .2

    i

    i i

    i

    i i

    Y n

    nn

    Y Y

    Y n

    Y X

    t t tR

    n n nnR

    t tR

    nn

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    2

    2

    1 1

    22

    Thus

    12

    2 1

    as .

    n i

    n n

    Z Y n

    i i

    ntn

    t tt R

    nn

    t nRe

    n

    n