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Transcript of ELEG413lec8
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Fundamental Antenna Parameters
1. Radiation Pattern
An antenna radiation pattern is defined as a graphical
representation of the radiation properties of the antenna
as a function of space coordinates. In most cases, the
radiation pattern is determined in the far-field region.
Radiation properties include radiation intensity, field
strength, phase or polarization.
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Coordinate System
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Idealized
Point Radiator Vertical Dipole Radar Dish
IsotropicOmnidirectional Directional
Types of Radiation Patterns
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Full Null Beamwidth
Between
1st NULLS
Radiation Pattern Lobes
Main lobe
Side lobes
Back lobes
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Radiation Pattern Lobes
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Field Regions
D
R1
R2
Reactive near-field region
3
1 62.0DR
Radiating near-field
(Fresnel) region
2
2 2D
R
Far-field (Fraunhofer)
region
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Radiation Intensity
Aside on Solid Angles
lengtharcrad0.1
r
sr0.1
2rareasurface
radianscecircumfrantotal 2224 rrSareasurfacetotal o
srr
So2
ddrds )sin(2
infinitesimal area
of surface of sphere
ddr
dsd )sin(
2
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Radiation Intensity
4
dUPsr
Wd
dPU
tot
rad
tot
rad
dsPPmW
ds
dPP rad
tot
rad
tot
radrad 2
radPrU2
),,( rPrad decays as 1/r2 in the far fieldsince
),( U will be independent of r
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Radiation Intensity
m ax
222
222*
),(),(
2),(
2
1~
2
1~~
2
1
),,(
U
UU
EEr
U
EEEHErPrad
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Radiation Intensity
Examples
0.1),(
),(
4),,(),(
4),,(
ma x
2
2
U
UU
constP
rPrU
rPrP
tot
radrad
tot
radrad
1. Isotropic radiator
2. Hertzian Dipole
)(sin),(
),(
)(sin42
)sin(42
1
2
1),(
0),,(
)sin(4
),,(
2
m ax
2
2
0
2
02222
0
U
UU
Il
r
eIlrEErU
rE
r
eIljrE
rj
rj
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Directive Gain
)(14
),(4
4
),(),(),(
m axm ax ydirectivit
P
UDD
P
U
P
U
U
UD
totrad
o
tot
rad
tot
radave
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Directivity
Examples
0.1
0.1),(
4),(
4),(
o
tot
rad
tot
rado
D
P
UD
PUU
1. Isotropic radiator
2. Hertzian Dipole
2
3
)(sin2
3),(4),(
3
8
42)sin()(sin
42),(
)(sin422
1),(
0),,(),sin(4
),,(
2
2
0
2
0 0
2
2
0
4
2
2
0222
o
tot
rad
tot
rad
rj
D
P
UD
Ildd
lIdUP
IlEErU
rEr
eljrE
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Antenna Gain
inputP
UG
),(4),(
POWER DENSITY IN A CERTAIN DIRECTION
DIVIDED BY THE TOTAL POWER RADIATED
POWER DENSITY IN A CERTAIN DIRECTION
DIVIDED BY THE TOTAL INPUT POWER
TO THE ANTENNA TERMINALS (FEED POINTS)
IF ANTENNA HAS OHMIC LOSS
THEN, GAIN < DIRECTIVITY
DIRECTIVITY
GAIN
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Antenna Gain
Sources of Antenna System Loss
1. losses due to impedance mismatches
2. losses due to the transmission line
3. conductive and dielectric losses in the antenna
4. losses due to polarization mismatches
According to IEEE standards the antenna gain does not include losses due to
impedance or polarization mismatches. Therefore the antenna gain only
accounts for dielectric and conductive losses found in the antenna itself. However
Balanis and others have included impedance mismatch as part of the antenna gain.
The antenna gain relates to the directivity through a coefficient called the
radiation efficiency (et)
),(),(),( DeeeDeG dcrt
conduction losses dielectric losses
1te
impedance mismatch
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Overall Antenna Efficiency
The overall antenna efficiency is a coefficient that accounts for all the different
losses present in an antenna system.
lossesdielectricconductore
lossesdielectrice
lossesconductione
mismatchimpedanceefficiencyreflectione
mismatchesonpolarizatie
eeeeeeee
cd
d
c
r
p
cdrp
e
dcrp
t
&
)(
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Reflection Efficiency
The reflection efficiency through a reflection coefficient (G) at the input (or feed)to the antenna.
)(
)(
12
G
G
impedanceoutputgeneratorR
impedanceinputantennaR
RR
RR
e
output
input
generatorinput
generatorinput
r
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Radiation Resistance
The radiation resistance is one of the few parameters that is relatively
straight forward to calculate.
2
4
2
),(22
oo
total
rad
radI
dU
I
P
R
Example: Hertzian Dipole
22
2
22
0 0
2
2
4
3
2
3
8
4
3
8
422
3
8
42
)sin()(sin
42
),(
2
ll
I
Il
R
Ildd
IldUP
o
o
rad
ootot
rad
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Radiation Resistance
Example: Hertzian Dipole (continued)
0063.09.750
9.7501
079.0
10000
1
3
2377
377100
1
3
2
3
8
4
3
8
422
2
22
2
2
r
rad
o
o
rad
e
R
andl
let
ll
I
Il
R
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Antenna Radiation Efficiency
radcd
radcd
RR
Re
Conduction and dielectric losses of an antenna are very difficult to separate and
are usually lumped together to form the ecd efficiency. Let Rcd represent the actual
losses due to conduction and dielectric heating. Then the efficiency is given as
For wire antennas (without insulation) there is no dielectric losses only conductor
losses from the metal antenna. For those cases we can approximate Rcd by:
22
ocd
b
lR
where b is the radius of the wire, is the angular frequency, is the conductivityof the metal and l is the antenna length
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Example Problem:
A half-wavelength dipole antenna, with an input impedance of 73 is to beconnected to a generator and transmission line with an output impedance of
50. Assume the antenna is made of copper wire 2.0 mm in diameter and theoperating frequency is 10.0 GHz. Assume the radiation pattern of the antenna is
Find the overall gain of this antenna
SOLUTION
First determine the directivity of the antenna.
)(sin),(3
o
BU
tot
rad
P
UD
),(4),(
697.1
3
16
)(sin3
16
4
3
)(sin4),(
m ax0
3
2
0
3
DD
B
BD o
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Example Problem: Continued
SOLUTION
Next step is to determine the gain
dBdBG
GG
G
DeeG cdr
14.2)636.1(log10)(
636.13
16964.0
)(sin3
16
964.0),(
),(),(
100
max0
3
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Antenna Type Gain (dBi) Gain over
Isotropic
Power Levels
Half
Wavelength
Dipole
1.76 1.5x
Cell Phone
Antenna
(PIFA)
3.0 2.0x 0.6 Watts
Standard Gain
Horn
15 31x
Cell phone
tower
antenna
6 4x
Large
ReflectingDish
50 100,000x
Small
Reflecting
Dish
40 10,000x
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Effective Aperture
plane wave
incidentAphysicalPload
incphysicalload WAP?
Question:
Answer: Usually NOT
inc
loadeffinceffload
W
PAWAP
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Directivity and Maximum Effective Aperture
(no losses)
Antenna #2
transmit receiver
R
Direction of wave propagation
Antenna #1
Atm, DtArm, Dr
oem DA
4
2
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Directivity and Maximum Effective Aperture
(include losses)
Antenna #2
transmit receiver
R
Direction of wave propagation
Antenna #1
Atm, DtArm, Dr
2*
22
4)1( awocdem DeA
G
conductor and
dielectric lossesreflection losses
(impedance mismatch)polarization mismatch
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Friis Transmission Equation (no loss)
Antenna #2
Antenna #1
R
The transmitted power density supplied by Antenna #1
at a distance R and direction (r,r)is given by:
24
),(
R
DPW
ttgtt
t
(t,t)
(r,r)
The power collected (received) by Antenna #2 is given by:
),(),(4
4
),(
4
),(
4
),(
2
2
22
rrgrttgt
t
r
rrgrttgtt
r
ttgtt
rtr
DDRP
P
D
R
DPA
R
DPAWP
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Friis Transmission Equation (no loss)
Antenna #2
Antenna #1
R
(t,t)
(r,r)
),(),(4
2
rrgrttgt
t
r DDRP
P
If both antennas are pointing in the direction of their maximum radiation pattern:
roto
t
r DDRP
P2
4
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Friis Transmission Equation ( loss)
Antenna #2
Antenna #1
R
(t,t)
(r,r)
2*
2
22),(),(
4
)1)(1( awrrgrttgttrcdrcdtt
r DD
R
ee
P
P
GG
conductor and
dielectric losses
transmitting antenna
conductor and
dielectric losses
receiving antenna
reflection losses in transmitter
(impedance mismatch)
reflection losses in receiving
(impedance mismatch)
polarization mismatch
free space loss factor
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Friis Transmission Equation: Example #1
A typical analog cell phone antenna has a directivity of 3 dBi at its operating frequency of
800.0 MHz. The cell tower is 1 mile away and has an antenna with a directivity of 6 dBi.Assuming that the power at the input terminals of the transmitting antenna is 0.6 W, and
the antennas are aligned for maximum radiation between them and the polarizations are
matched, find the power delivered to the receiver. Assume the two antennas are well
matched with a negligible amount of loss.
nWwattsPr 65.142609.34414
375.06.0
2
2*maxmax
2
22
4)1)(1( awrttrcdrcdtt
r
DDReeP
P
GG
= 0 = 0= 1= 1= 1
0.410
0.210
375.06800
83
10/6m ax
10/3m ax
r
t
D
D
me
efc
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Friis Transmission Equation: Example #2
A half wavelength dipole antenna (max gain = 2.14 dBi) is used to communicate from an
old satellite phone to a low orbiting Iridium communication satellite in the L band (~ 1.6GHz). Assume the communication satellite has antenna that has a maximum directivity of
24 dBi and is orbiting at a distance of 781 km above the earth. Assuming that the power at
the input terminals of the transmitting antenna is 1.0 W, and the antennas are aligned for
maximum radiation between them and the polarizations are matched, find the power
delivered to the receiver. Assume the two antennas are well matched with a negligible
amount of loss.
pWwattsPr 15.025164.1781,0004
1875.00.1
2
2*maxmax
2
22
4)1)(1(
awrttrcdrcdt
t
r DDR
eeP
P
GG
= 0 = 0= 1= 1= 1
0.25110
64.110
1875.06800
83
10/24m ax
10/14.2m ax
r
t
D
D
me
e
f
c
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Friis Transmission Equation: Example #2
A roof-top dish antenna (max gain = 40.0 dBi) is used to communicate from an old satellite
phone to a low orbiting Iridium communication satellite in the Ku band (~ 12 GHz).Assume the communication satellite has antenna that has a maximum directivity of 30 dBi
and is orbiting at a distance of 36,000 km above the earth. How much transmitter power is
required to receive 100 pW of power at your home. Assume the antennas are aligned for
maximum radiation between them and the polarizations are matched, find the power
delivered to the receiver. Assume the two antennas are well matched with a negligible
amount of loss.
Wwatts
Pt 82
1000000,1036,000,0004
025.0
101002
12
2*maxmax
2
22
4)1)(1(
awrttrcdrcdt
t
r DDR
eeP
P
GG
= 0 = 0= 1= 1= 1
0.100010
000,1010
025.06800
83
10/30m ax
10/40m ax
t
r
D
D
me
e
f
c
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Radar Range Equation
Definition: Radar cross section or echo area of a target is defined as the area when interceptingthe same amount of power which, when scattered isotropically, produces at the receiver the same
power density as the actual target.
22
24lim
4lim m
W
WR
R
WW
inc
s
R
inc
Rs
(radar cross section) m2
R (distance from target) m
Ws (scattered power density) W/m2
Winc (incident power density) W/m2
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Radar Range Equation (no losses)
Power density incident on the target is a function
of the transmitting antenna and the distance
between the target and transmitter:
24
),(
t
ttgtt
incR
DPW
The amount of power density scattered by the
target at the location of the receiver is then given
by:
22)4(
),(
4 rt
ttgtt
r
incsRR
DP
RWW
The amount of power delivered by the receiver is
then given by:
4),(
)4(
),( 2
2 rrgr
rt
ttgtt
rsr DRR
DPAWP
4
),(),(
)4( 2
2rrgrttgt
rtt
rDD
RRP
P ),,,( rrtt
Note that in general:
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Radar Range Equation (losses)
2*
2
22
44
),(),()1)(1( aw
rt
rrgrttgt
trcdrcdt
t
r
RR
DDee
P
P
GG
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Radar Cross Section (RCS)
Definition: Radar cross section or
echo area of a target is defined as
the area when intercepting
the same amount of power which,
when scattered isotropically,
produces at the receiver the same
power density as the actual target.
22
24lim
4lim m
W
WRR
WWinc
s
R
inc
Rs
2
2
2
22
2
2
2 4lim4lim mE
ERm
E
ER
inc
scat
Rinc
scat
R
),,,( rrtt rtrt ,
Transmitter and receiver not in
the same location (bistatic RCS)
rtrt ,Transmitter and receiver in the
same location (usually the same
antenna) called mono-static RCS
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Radar Cross Section (RCS)
RCS Customary Notation:Typical RCS values can span 10-5m2
(insect) to 106 m2 (ship). Due to the
large dynamic range a logarithmic
power scale is most often used.
1log10log10
22
2 1010m
ref
m
dBmdBsm
100 m2 20 dBsm10 m2 10 dBsm1 m2 0 dBsm0.1 m2 -10 dBsm0.01 m2 -20 dBsm